原方程可化为$3 x ( x - 1 ) - 2 ( x - 1 ) = 0$，即$( x - 1 ) ( 3 x - 2 ) = 0$，所以$x - 1 = 0$或$3 x - 2 = 0$，解得$x _ {1} = 1$，$x _ {2} = \frac {2} {3}$.